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Re: \times 3/2
From: |
David Bobroff |
Subject: |
Re: \times 3/2 |
Date: |
20 Oct 2004 06:11:51 +0000 |
On Wed, 2004-10-20 at 04:55, D Josiah Boothby wrote:
> Hello, list,
>
> I'm trying to get a tuplet of two quarter notes in a 9/8 measure (so the
> beat is a dotted quarter), but what I get is two quarter notes over the
> space of a dotted half note. I think I can see why this is, but is there
> a way to get what I want? Or is the score from which I'm copying wrong
> (in which case I should have two eighths instead of two quarters)?
>
> \version "2.2.6"
>
> \header {
> title = "tuplet test"
> }
>
> \score {
> \notes \relative c'' {
> \time 9/8
> \times 3/2 { bes4 g } d'2. ~
> d8
> }
> \paper {
> raggedright = ##t
> }
> }
I had a similar problem recently and was shown this solution:
Change this:
\times 3/2 { bes4 g } d'2. ~
To this:
\times 3/2 { bes4*1/2 g } d'2. ~
...and all should be fine.
-David
- \times 3/2, D Josiah Boothby, 2004/10/20
- Re: \times 3/2,
David Bobroff <=