Re: A question on "##t"

[Damian leGassick]

actually, this confuses me too

if the # puts lilypond into scheme mode, does that mean that the  
equals-sign in #'merge-differently-headed = ##t  is not scheme? if it  
is, then why not #'merge-differently-headed = #t  ?

d


On 24 Jan 2008, at 16:06, Mats Bengtsson wrote:

> Martin Seng Hin Yew wrote:
> > Bertalan Fodor (LilyPondTool) wrote:
> > > Everything beginning with a # is a Scheme-language expression.
> > > So this sets the property called 'merge-differently-headed to the  
> > > value #t
> > > #t is the expression meaning true in Scheme.
> > Hi Bertalan Fodor,
> >
> > Okay...assume i knew the word "true" (means =yes or 1, right?),  
> > but ##t got double #, so what does the other # means?
> He already told you :-) The first # tells LilyPond that "here comes  
> a Scheme
> expression", the "#t" which follows is the actual Scheme code.
>
>   /Mats
>
>
> _______________________________________________
> lilypond-user mailing list
> address@hidden
> http://lists.gnu.org/mailman/listinfo/lilypond-user