actually, this confuses me too
if the # puts lilypond into scheme mode, does that mean that the
equals-sign in #'merge-differently-headed = ##t is not scheme? if
it is, then why not #'merge-differently-headed = #t ?
d
On 24 Jan 2008, at 16:06, Mats Bengtsson wrote:
Martin Seng Hin Yew wrote:
Bertalan Fodor (LilyPondTool) wrote:
Everything beginning with a # is a Scheme-language expression.
So this sets the property called 'merge-differently-headed to
the value #t
#t is the expression meaning true in Scheme.
Hi Bertalan Fodor,
Okay...assume i knew the word "true" (means =yes or 1, right?),
but ##t got double #, so what does the other # means?
He already told you :-) The first # tells LilyPond that "here
comes a Scheme
expression", the "#t" which follows is the actual Scheme code.
/Mats
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