Re: different rhythmic units for tuplet's numerator and denominator

[James E. Bailey]

Am 08.07.2008 um 00:04 schrieb Uri Sala:

Dear James,

Thanks but, again, this is misleading, since the numbers in the bracket would be 6:5 but there would be 3 notes inside the tuplet. I don't have 6 attacks but 3. This is the kind of cheating I do in Sibelius, and that I would like to avoid if possible. Sorry to be so demanding, but isn't this what lilypond should be about? To output exactly what you want?

Cheers,

Uri

On MondayJul 7, at MonJul 7|23:44 , James E. Bailey wrote:

Am 07.07.2008 um 22:14 schrieb Uri Sala:

It is a bit more convoluted than that. I will try to make myself clearer:

I want to write 3 against 5.

a tuplet… is a compression of the duration of a rhythmic value. V

\version "2.11.50"
\relative {
  \time 5/16
  c16 d e f g
  \times 5/6 {a8 f d}
}

So, if I understand correctly, you want 3 eighth notes in the space of 3.5 eighth notes, or as you put it, 3 eighth notes in the space of 5 sixteenth notes. You want to have a bracket containing 3 eighth notes and then the number defining the tuplet to be, I'm assuming, 3 (eighth note) : 5 (sixteenth)? Do I understand that correctly? If so:

\version "2.11.50"

\relative {

   \time 5/16

   c16 d e f g

   \override TupletNumber #'text = #(markup #:italic "3" #:fontsize -3 #:note "8" 1  #:italic ":5"  #:fontsize -3 #:note "16" 1)

   \times 5/6 {a8 f d}

}

I'm sure you don't mean to be, but you come off sounding kind of whiny and complaining, and expecting that someone else should solve your problems for you. That's not a really good way to get help, especially from a volunteer project.

That being said, this is the last time I'll help you with this problem. If you can't figure it out on your own, then perhaps you should find a better way being right, in the face of everone else.

http://www.catb.org/~esr/faqs/smart-questions.html