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## Re: different rhythmic units for tuplet's numerator and denominator

 From: James E. Bailey Subject: Re: different rhythmic units for tuplet's numerator and denominator Date: Tue, 08 Jul 2008 01:19:14 +0200

 Am 08.07.2008 um 00:04 schrieb Uri Sala:Dear James,Thanks but, again, this is misleading, since the numbers in the bracket would be 6:5 but there would be 3 notes inside the tuplet. I don't have 6 attacks but 3. This is the kind of cheating I do in Sibelius, and that I would like to avoid if possible. Sorry to be so demanding, but isn't this what lilypond should be about? To output exactly what you want?Cheers,UriOn MondayJul 7, at MonJul 7|23:44 , James E. Bailey wrote:Am 07.07.2008 um 22:14 schrieb Uri Sala:It is a bit more convoluted than that. I will try to make myself clearer:I want to write 3 against 5.a tuplet… is a compression of the duration of a rhythmic value. V\version "2.11.50"\relative {   \time 5/16   c16 d e f g   \times 5/6 {a8 f d}}So, if I understand correctly, you want 3 eighth notes in the space of 3.5 eighth notes, or as you put it, 3 eighth notes in the space of 5 sixteenth notes. You want to have a bracket containing 3 eighth notes and then the number defining the tuplet to be, I'm assuming, 3 (eighth note) : 5 (sixteenth)? Do I understand that correctly? If so:\version "2.11.50"\relative {   \time 5/16   c16 d e f g   \override TupletNumber #'text = #(markup #:italic "3" #:fontsize -3 #:note "8" 1  #:italic ":5"  #:fontsize -3 #:note "16" 1)   \times 5/6 {a8 f d}}I'm sure you don't mean to be, but you come off sounding kind of whiny and complaining, and expecting that someone else should solve your problems for you. That's not a really good way to get help, especially from a volunteer project.That being said, this is the last time I'll help you with this problem. If you can't figure it out on your own, then perhaps you should find a better way being right, in the face of everone else.http://www.catb.org/~esr/faqs/smart-questions.html

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