Re: is shapeSlur broken?

[Jan-Peter Voigt]

Hello Urs,

yes there was a syntax change:
you might try

shapeSlur = #(define-music-function (parser location offsets)(list?)
  #{
    \once \override Slur #'control-points = $(shape-slur offsets)
  #})

Variables in musicfunctions now are available by there name without the 
preceding $.
The $-sign now introduces a scheme-expression and returns the result 
directly ... now here should be more explanation, that I am not able to 
put in words right now ;-)

HTH
Cheers, Jan-Peter

On 27.04.2012 10:11, Urs Liska wrote:
> Hi list,
>
> the shapeSlur function from the LSR 
> (http://lsr.dsi.unimi.it/LSR/Snippet?id=777) doesn't seem to work 
> anymore (at least for me).
>
> That's the 'entrance' function:
>
> shapeSlur =
> #(define-music-function (parser location offsets)
>                         (list?)
>   #{
>     \once \override Slur #'control-points = #(shape-slur $offsets)
>   #})
>
>
> When calling this function I get the error:
>
> Fehler: GUILE signalisierte einen Fehler für den hier beginnenden 
> Ausdruck
>     \once \override Slur #'control-points = #
>                                              (shape-slur $offsets)
>
> then
>
> Warnung: Typprüfung für »control-points« gescheitert; Wert 
> »#<unspecified>« muss vom Typ »list« sein
>
> and finally
>
> Unbound variable: $offsets
>
> From what I see I assume that this is due to some change in syntax at 
> some point (the last time I recall using this function was with 2.14.0).
> But as you know I'm still quite lost with Scheme, so I can't neither 
> verify nor fix this, and so I'd be gracious for any advice. Of course 
> I can't be sure that this type check at the calling of the 'main' 
> function is all there is to it, but lilyPond doesn't even get to call 
> shape-slur ...
>
> Best
> Urs
>
>
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