Re: Chord Inversion Problem.

[AlanRobertClark]

pls <p.l.schmidt <at> gmx.de> writes:

> c/e (which is actually the first inversion) doesn't work correctly in
chordmode. This is a known issue. But
> there is a workaround. I use two different variables: one for the chords and
one for the chord names (see
> below). And I use this construct: c1:3.5.8^1 in chordmode. This way any
inversion can be defined, e.g.:
> c:maj7/e = c:3.5.7+.8^1

Thank you so very much. This is **exactly** what I want. It works perfectly! Now
I can get on with setting the real exercises for the kids!

Greetings from a chilly South Africa, Alan.