| Hi,
3. Q: I have a program that does not create its own pid file. Since monit requires all programs to have a pid file, what do I do?
A: Create a wrapper script and have the script create a pid file
before it starts the program. Below you will find an example
script for starting an imaginary program (a Java program in this
case). Assuming that the script is saved in a file called
/bin/xyz, you can call this script from monit by using the
following in monitrc:
check process xyz with pidfile /tmp/xyz.pid
start = "/bin/xyz start"
stop = "/bin/xyz stop"
--8<--- (cut here)
#!/bin/bash
export JAVA_HOME=/usr/local/java/
export DISPLAY=localhost:0.0
CLASSPATH=ajarfile.jar:.
case $1 in
start)
echo $$ > /tmp/xyz.pid;
exec 2>&1 java -cp ${CLASSPATH} org.something.with.main \
1>/tmp/xyz.out
;;
stop)
kill `cat /tmp/xyz.pid` ;;
*)
echo "usage: xyz {start|stop}" ;;
esac
--8<---- (cut here)
the example contains the stop method as well (kill `cat /tmp/xyz.pid`).
Cheers, Martin
P.S. we plan to add the possibility to control the services without the pidfile need as well (lot of users asked for it).
Hello Martin,
Thanks a lot for your good work.
I work in a VAS company. We have developed a few java daemons.
Monit is based on processID, my daemons do not have pid.
I understand that I should create a rapper scripts
One of my daemons is called, say xyz, locate in /app/japp/
i.e.
/app/japp/xyz.java
/app/japp/xyz.class
/app/japp/error_log
/app/japp/info_log
In my monitrc i should have someting like
check process xyz with pidfile /tmp/xyz.pid
start = "java /app/japp/xyz"
stop = " ???? stop"
I cant figure out how to create /tmp/xyz.pid and hoe to start or stop it in monit.
with regards
Francis
--
To unsubscribe:
http://lists.nongnu.org/mailman/listinfo/monit-general
|