[Octave-bug-tracker] [bug #54698] Precedence of call/indexing operator over transpose operator

[Mike Miller]

Follow-up Comment #22, bug #54698 (project octave):

jwe - I haven't looked at the parser yet, I've only been trying to propose a
simple change to the docs to match how Octave actually works. Maybe the docs
are fine the way they are now, but I think I agree with the OP that somewhere
it should be explained that

A.'(m:n)

is evaluated as

(A.')(m:n)

even though the parentheses operator has higher precedence. I don't want to
change anything in the implementation of the parser. I just think there should
be an explanation as to why that is.

OP - For numeric types, the expressions (A^B)' and A^(B') are equivalent, so I
considered it a non-problem. But yes, for user-defined types that does change
the order of operation. Withdrawn.

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