Re: stable sorts

[Michael D Godfrey]

On 08/25/2012 09:55 PM, Ed Meyer wrote:

Just because it has kept the order of x(2) and x(3) does not necessarily mean it is a stable sort;
an unstable sort can do either but a stable sort is guaranteed to keep the original order.

--
Ed Meyer

Yes.  But, this thread started from an error on my part.  I had thought
that Ben's fix for interp1 was based on the Octave sort not being stable.
The real problem was with the direction of the discontinuity mechanism
in interp1.

I am pretty sure that Octave sort is stable, but this could be checked
more, of course.

Michael