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Re: MATLAB fminbnd() output
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From: |
Richard Crozier |
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Subject: |
Re: MATLAB fminbnd() output |
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Date: |
Sun, 02 Sep 2012 15:18:53 +0100 |
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User-agent: |
Mozilla/5.0 (Windows NT 5.1; rv:7.0.1) Gecko/20110929 Thunderbird/7.0.1 |
On 02/09/2012 14:32, Júlio Hoffimann wrote:
fminbnd(@cos,3,4,optimset("TolX",1e-4,"Display","off"))
fminbnd(@cos,3,4,optimset("TolX",1e-4,"Display","off","MaxIter",3))
fminbnd(@cos,3,4,optimset("TolX",1e-4,"Display","notify"))
fminbnd(@cos,3,4,optimset("TolX",1e-4,"Display","notify","MaxIter",3))
fminbnd(@cos,3,4,optimset("TolX",1e-4,"Display","final"))
fminbnd(@cos,3,4,optimset("TolX",1e-4,"Display","final","MaxIter",3))
fminbnd(@cos,3,4,optimset("TolX",1e-4,"Display","iter"))
fminbnd(@cos,3,4,optimset("TolX",1e-4,"Display","iter","MaxIter",3))
R2012a
>> fminbnd(@cos,3,4,optimset('TolX',1e-4,'Display','off'))
fminbnd(@cos,3,4,optimset('TolX',1e-4,'Display','off','MaxIter',3))
fminbnd(@cos,3,4,optimset('TolX',1e-4,'Display','notify'))
fminbnd(@cos,3,4,optimset('TolX',1e-4,'Display','notify','MaxIter',3))
fminbnd(@cos,3,4,optimset('TolX',1e-4,'Display','final'))
fminbnd(@cos,3,4,optimset('TolX',1e-4,'Display','final','MaxIter',3))
fminbnd(@cos,3,4,optimset('TolX',1e-4,'Display','iter'))
fminbnd(@cos,3,4,optimset('TolX',1e-4,'Display','iter','MaxIter',3))
ans =
3.1416e+000
ans =
3.1357e+000
ans =
3.1416e+000
Exiting: Maximum number of iterations has been exceeded
- increase MaxIter option.
Current function value: -0.999983
ans =
3.1357e+000
Optimization terminated:
the current x satisfies the termination criteria using OPTIONS.TolX of
1.000000e-04
ans =
3.1416e+000
Exiting: Maximum number of iterations has been exceeded
- increase MaxIter option.
Current function value: -0.999983
ans =
3.1357e+000
Func-count x f(x) Procedure
1 3.38197 -0.971249 initial
2 3.61803 -0.888633 golden
3 3.23607 -0.995541 golden
4 3.13571 -0.999983 parabolic
5 3.1413 -1 parabolic
6 3.14159 -1 parabolic
7 3.14156 -1 parabolic
8 3.14163 -1 parabolic
Optimization terminated:
the current x satisfies the termination criteria using OPTIONS.TolX of
1.000000e-04
ans =
3.1416e+000
Func-count x f(x) Procedure
1 3.38197 -0.971249 initial
2 3.61803 -0.888633 golden
3 3.23607 -0.995541 golden
4 3.13571 -0.999983 parabolic
Exiting: Maximum number of iterations has been exceeded
- increase MaxIter option.
Current function value: -0.999983
ans =
3.1357e+000
Regards,
Richard
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