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Re: [Qemu-devel] i386 emulation bug: mov reg, [addr]


From: Avi Kivity
Subject: Re: [Qemu-devel] i386 emulation bug: mov reg, [addr]
Date: Tue, 15 Dec 2009 21:54:04 +0200
User-agent: Mozilla/5.0 (X11; U; Linux x86_64; en-US; rv:1.9.1.5) Gecko/20091203 Fedora/3.0-3.13.rc2.fc12 Thunderbird/3.0

On 12/15/2009 08:48 PM, Clemens Kolbitsch wrote:
Hi list,

I'm experiencing a strange emulation bug with the op-code below. The
instruction raises a segfault in the application (running on the guest),
however, if I enable KVM to run the exact same application, no segfault is
raised.

0x0080023b:       8b 04 65 11 22 33 44    mov regEAX, [0x44332211]

where "11 22 33 44" is just some address. According to gdb (on a 32bit little-
endian machine), this instruction can be disassembled as a "mov address to
reg-eax".

This is an odd encoding for this instruction, since there is a shorter one possible (8b 05 11 22 33 44). So it is possible there is a bug in qemu that has never been triggered because compilers/assemblers don't generate this encoding.

btw, binutils disassembles this as

  8b 04 65 11 22 33 44     mov    0x44332211(,%eiz,2),%eax

I guess %eiz is some mnemonic for a "zero register" so the assembly can be reassembled into a 7-byte instruction later.

--
Do not meddle in the internals of kernels, for they are subtle and quick to 
panic.





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