[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]
[Qemu-devel] [Bug 1480562] [NEW] register values in sp804 timer
From: |
T-T Yu |
Subject: |
[Qemu-devel] [Bug 1480562] [NEW] register values in sp804 timer |
Date: |
Sat, 01 Aug 2015 14:46:11 -0000 |
Public bug reported:
In the arm_timer.c, when first reading the load register, I got 0.
...
case 0: /* TimerLoad */
...
According to the specification at
http://infocenter.arm.com/help/index.jsp?topic=/com.arm.doc.ddi0271d/index.html,
"The minimum valid value for TimerXLoad is 1". Is the initial value supposed
to be 0xffffffff?
When the 5th and 7th bit in Control Register are set, RIS and MIS remain 0. But
should they be enabled (i.e., 0x1 and 0x1) as both interrupt and timer module
are set.
Thanks.
** Affects: qemu
Importance: Undecided
Status: New
--
You received this bug notification because you are a member of qemu-
devel-ml, which is subscribed to QEMU.
https://bugs.launchpad.net/bugs/1480562
Title:
register values in sp804 timer
Status in QEMU:
New
Bug description:
In the arm_timer.c, when first reading the load register, I got 0.
...
case 0: /* TimerLoad */
...
According to the specification at
http://infocenter.arm.com/help/index.jsp?topic=/com.arm.doc.ddi0271d/index.html,
"The minimum valid value for TimerXLoad is 1". Is the initial value supposed
to be 0xffffffff?
When the 5th and 7th bit in Control Register are set, RIS and MIS remain 0.
But should they be enabled (i.e., 0x1 and 0x1) as both interrupt and timer
module are set.
Thanks.
To manage notifications about this bug go to:
https://bugs.launchpad.net/qemu/+bug/1480562/+subscriptions
- [Qemu-devel] [Bug 1480562] [NEW] register values in sp804 timer,
T-T Yu <=