On Tue, 17 Jun 2014, Tom Musta wrote:
I am looking at the test case source code and do not see how you
are setting the reserved bit. Maybe I am missing some cleverness in
how the test is built?
Probably I should have written it more straight-forward but I wanted
it to be possible to change it for other tests easily so it's a bit
tricky. Basically I get the code location by a bl then fetching the
link register:
asm volatile("mfcr %0 \n\t"
"bl 1f \n\t"
"mfcr %1 \n\t"
"mflr 10 \n\t"
and then set the bit with the next three lines after testing the
normal case:
"lwz %0, 36(10) \n\t"
"ori %0, %0, 1 \n\t"
"stw %0, 36(10) \n\t"
Then test again with the bit set:
"mfcr %0 \n\t"
"bl 1f \n\t"
"mfcr %2 \n\t"
and exit:
"b 2f \n\t"
"1: stwx %0, %4, %6 \n\t" <<<<<<<<<<<<< just a
normal stwx, right?
"blr \n\t"
"2: \n\t"
: "=&r"(cr), "=&r"(cr1), "=&r"(cr2), "=m"(val)
: "r"(&val), "m"(val), "r"(8)
: "r8", "r9", "r10", "cc", "memory");
prom_printf("old cr (mem):\t%#x\n", val);
prom_printf("old cr (reg):\t%#x\n", cr);
prom_printf("new cr1 (reg):\t%#x\n", cr1);
prom_printf("new cr2 (reg):\t%#x\n", cr2);
}
But the objdump of your test binary does not show that it is set
either:
It should show in a debugger the second time the stwx is called (it
did for me).