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Re: $srcdir

From: Philip Willoughby
Subject: Re: $srcdir
Date: Wed, 5 Mar 2003 21:16:04 +0000 (GMT)

Today, Dr. David Kirkby wrote:

>I'm sorry I don't really know if this is an automake issue or an
>autoconf one, so please excuse the posting to both groups. I'm
>confused just how to best refer to files and in particular the use of
>$srcdir, which I assumed refereed to the directory 'src' below the top
>directory of a package, but seems to be undefined when I try to use
>it. Putting 'echo $srcdir' in a test script, just echoes a blank line,
>with no directory information.

I think this is right - no doubt someone will correct me if not ;-).

$srcdir refers to the directory containing the input Makefile the Makefile
you're looking at it from was generated from.  Let me try explaining that

If you have the following structure:


and then you make a build dir and run configure in it you'll have:


In which case at the top level $srcdir will be set to ../ and in the src
dir it will be set to ../../src/

Of course, most people don't use separate build directories, and thus
$srcdir is left empty - you don't need to see files in a separate
directory in this case.

Anyway, you probably want to use $top_srcdir, which is the root of the
original package - thus if you need to refer to the src directory in the
source area you should use $top_srcdir/src/.  Think carefully though - if
you want to refer to a built component you should use $top_builddir instead
of $top_srcdir, or everyone who uses separate build directories as standard
(in other words, me ;-)) will be very annoyed...


Philip Willoughby

Systems Programmer, Department of Computing, Imperial College, London, UK
echo address@hidden | tr "bizndfohces" "pwgd9ociaku"

Why reinvent the wheel? . . . . . . . . . Because we can make it rounder...

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