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Re: How to exit if program is not found

From: Timothy Madden
Subject: Re: How to exit if program is not found
Date: Fri, 15 Jun 2012 16:16:36 +0300
User-agent: Mozilla/5.0 (X11; Linux x86_64; rv:10.0.5) Gecko/20120607 Thunderbird/10.0.5

On 06/14/2012 07:37 PM, Timothy Madden wrote:
On 06/14/2012 07:07 PM, Roger Pau Monné wrote:
On Thu, Jun 14, 2012 at 5:01 PM, Timothy
Madden<address@hidden> wrote:

I see in the info pages that autoconf macros check for various
programs and
set a variable if found, but how do I get the behaviour I see in most
configure programs to exit with an error if a program is not found ?

I usually use the following macro:

[AC_PATH_PROG([$1], [$2], [no])
if test x"${$1}" == x"no"
AC_MSG_ERROR([Unable to find $2, please install $2])

So on my I make the following calls:


Where "PERL" is the name of the variable where to store the path, and
"perl" is the name of the program to search for.

How about the predefined programs ?

AC_PROG_YACC might set YACC to 'bison -y', how would I check that 'bison
-y' is found or is on path ?

I find that the following command
        command -v bison -y
works as expected and returns 0 if bison is found or non-zero if there is no bison.

What do you know about the portability of `command` ? Can I use it in my ?

Or is there a better way to exit after AC_PROG_YACC if bison is not found ? Or to exit if AC_PROG_CXX does not find a C++ compiler ?

And really, is there no support in autoconf itself for this ?

Is there no flag or option to make the resulting configure exit automatically if any of the checks fail ?

Thank you,
Timothy Madden

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