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## [avr-gcc-list] efficiency of assigning bits

**From**: |
Jamie Morken |

**Subject**: |
[avr-gcc-list] efficiency of assigning bits |

**Date**: |
Sun, 13 Mar 2005 06:42:43 -0800 |

Hi,
I am trying to turn two bits off on a port as
quickly as possible, how do these two methods
compare:
PORTD = (PORTD & ~PD1) & ~PD4;
or:
cbi(PORTD, PD1);
cbi(PORTD, PD4);
I am assuming these are equivalent. I am learning
about bit operators so I can't be sure yet! :)
cheers,
Jamie

**[avr-gcc-list] efficiency of assigning bits**,
*Jamie Morken* **<=**
**Re: [avr-gcc-list] efficiency of assigning bits**, *E. Weddington*, `2005/03/14`
**Re: [avr-gcc-list] efficiency of assigning bits**, *David Willmore*, `2005/03/14`
**Re: [avr-gcc-list] efficiency of assigning bits**, *E. Weddington*, `2005/03/14`
**Re: [avr-gcc-list] efficiency of assigning bits**, *Erik Walthinsen*, `2005/03/14`
**Re: [avr-gcc-list] efficiency of assigning bits**, *Jesper Hansen*, `2005/03/14`
**Re: [avr-gcc-list] efficiency of assigning bits**, *E. Weddington*, `2005/03/14`
**Re: [avr-gcc-list] efficiency of assigning bits**, *Erik Walthinsen*, `2005/03/14`
**Re: [avr-gcc-list] efficiency of assigning bits (OT)**, *Hugo González Monteverde*, `2005/03/15`
**Re: [avr-gcc-list] efficiency of assigning bits**, *Dave Hansen*, `2005/03/14`
**Re: [avr-gcc-list] efficiency of assigning bits**, *Christof Krueger*, `2005/03/14`