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Re: [Axiom-developer] please check your Schaums

From: Doug Stewart
Subject: Re: [Axiom-developer] please check your Schaums
Date: Mon, 28 Apr 2008 07:10:17 -0400
User-agent: Thunderbird (X11/20080227)

address@hidden wrote:
In 14.661 Schaums claims:

integral acoth(x/a) = x*acoth(x)+a/2*log(x^2-a^2)

Axiom claims

integral acoth(x/a) = x*acoth(x/a)+a/2*log(x^2-a^2)

Is this a Schaums typo?


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My schaums is the same as your Schaums but it is old (not as old as yours) I have a New Schaums at work But I will not Be in to work today :-)

My Maxima agrees with Axium.

(%o8) (a*log(x^2/a^2-1))/2+x*acoth(x/a)

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