|
| From: | Dr . Jürgen Sauermann |
| Subject: | Re: Question on scalar extension of left arg |
| Date: | Fri, 30 Jul 2021 17:56:23 +0200 |
| User-agent: | Mozilla/5.0 (X11; Linux x86_64; rv:78.0) Gecko/20100101 Thunderbird/78.11.0 |
Looking at this post I think there is a tiny bug in the implementation of each:
(⍳6) {⍺,⍵}¨ ⍳5
1 1 2 2 3 3 4 4 5 5
(⍳5) {⍺,⍵}¨ ⍳6
INDEX ERROR
μ-Z__vA_LO_EACH_vB[2] (μ-N⊃μ-Z)←(μ-N⊃μ-A)μ-LO ^ ^
I think both should give a LENGTH ERROR.
On Thu, Jul 29, 2021 at 10:48:52PM -0700, Russtopia wrote:
w
┌→─────┐
│listen│
└──────┘
cl
┌→────────────────────────────────────────────┐
│┌→──────┐ ┌→─────┐ ┌→─────┐ ┌→─────┐ ┌→─────┐│
││enlists│ │google│ │inlets│ │banana│ │tinsel││
│└───────┘ └──────┘ └──────┘ └──────┘ └──────┘│
└∊────────────────────────────────────────────┘
w is_anagram_of ¨ cl ⍝ <-- Should this not implicitly expand left arg?
Look at the shapes, w is not a scalar but a vector of length 6 and cl is a vector of length 5. No scalar extension is possible, but a length error.
What you wanted is simply:
(⊂w) is_anagram_of¨ cl
0 0 1 0 1
(∊1 (⍴cl))⍴⊂w
┌→───────────────────────────────────────────┐
↓┌→─────┐ ┌→─────┐ ┌→─────┐ ┌→─────┐ ┌→─────┐│
││listen│ │listen│ │listen│ │listen│ │listen││
│└──────┘ └──────┘ └──────┘ └──────┘ └──────┘│
└∊───────────────────────────────────────────┘
w w w w w
┌→───────────────────────────────────────────┐
│┌→─────┐ ┌→─────┐ ┌→─────┐ ┌→─────┐ ┌→─────┐│
││listen│ │listen│ │listen│ │listen│ │listen││
│└──────┘ └──────┘ └──────┘ └──────┘ └──────┘│
└∊───────────────────────────────────────────┘
These are not the same. See that arrow on the left border of boxed representation?
((∊1 (⍴cl))⍴⊂w) is_anagram_of ¨ cl ⍝ <-- ?? Why does this not work as (w w w w w)?
RANK ERROR
((∈1(⍴cl))⍴⊂w)is_anagram_of¨cl
^ ^
w w w w w ←→ 5⍴⊂w ⍝ a 5-element vector
((∊1 (⍴cl))⍴⊂w) ←→ 1 5⍴⊂w ⍝ a 1-by-5 matrix
-k
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