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Re: Modifying $0?

From: Davy Durham
Subject: Re: Modifying $0?
Date: Thu, 08 Jul 2004 12:52:03 -0400
User-agent: Mozilla/5.0 (X11; U; Linux i686; en-US; rv:1.6) Gecko/20040115

Paul Jarc wrote:

Ah: "." sets the positional parameters if any are given, or leaves
them unchanged otherwise.  So we can ensure that we specify at least
one, and then get rid of it later:

if [ "$0" != what-you-want ]; then
 exec bash -c '. "$1" "$@"' what-you-want "$0" ${1+"$@"}

So now the "." command is '. /path/to/script /path/to/script args...'.
Even if there are no args, there is at least one extra argument for
".", so it will always set the positional parameters.  Then we shift
off the duplicate /path/to/script.

That's similar to what I ended up doing... Here's the final result frrom all your help: (I wanted it all as a single line as well)

[[ "$0" != what-i-want ]] && exec "$SHELL" -c 'source "$@"' what-i-want "$0" foo ${1+"$@"} || shift 1

So, I put the extra parameter outside the -c '...' parameter which seems to work fine too. (Foresee any problems with that?)

Thanks yet again,

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