Re: Timing an operation

[Matthew_S]

Thanks Paul and Chet;

They both do the same thing and that's exactly what I was looking for.

Thanks again,

Matthew.


Chet Ramey wrote:
> 
> Paul Jarc wrote:
> 
>> date1=`perl -e 'print time()'`
>> ...
>> date2=`perl -e 'print time()'`
>> interval=`expr "$date2" - "$date1"`
> 
> This general approach can be used without invoking any external programs:
> 
> date1=$SECONDS
> ...
> date2=$SECONDS
> interval=$(( $date2 - $date1 ))
> 
> Chet
> -- 
> ``The lyf so short, the craft so long to lerne.'' - Chaucer
>                      Live Strong.  No day but today.
> Chet Ramey, ITS, CWRU    chet@case.edu   
> http://cnswww.cns.cwru.edu/~chet/
> 
> 
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> 

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