Re: logical XOR

[Robert Millan [ackstorm]]

On Thu, Jun 28, 2007 at 06:58:25PM -0400, Chet Ramey wrote:
> ackstorm wrote:
> > Configuration Information [Automatically generated, do not change]:
> > Machine: i486
> > OS: linux-gnu
> > Compiler: gcc
> > Compilation CFLAGS:  -DPROGRAM='bash' -DCONF_HOSTTYPE='i486' 
> > -DCONF_OSTYPE='linux-gnu' -DCONF_MACHTYPE='i486-pc-linux-gnu' 
> > -DCONF_VENDOR='pc' -DLOCALEDIR='/usr/share/locale' -DPACKAGE='bash' -DSHELL 
> > -DHAVE_CONFIG_H   -I.  -I../bash -I../bash/include -I../bash/lib   -g -O2
> > uname output: Linux acklap03 2.6.18-4-686 #1 SMP Wed May 9 23:03:12 UTC 
> > 2007 i686 GNU/Linux
> > Machine Type: i486-pc-linux-gnu
> > 
> > Bash Version: 3.1
> > Patch Level: 17
> > Release Status: release
> > 
> > Description:
> >     There's bitwise AND and bitwise OR, and logical AND and logical OR, but
> >     for XOR there's only the bitwise version.  Would be nice if the logical
> >     XOR would also be present (^^).
> 
> (!a) != (!b)
> 
> should work acceptably for the situations such an operator would be used.

I'm not sure what you mean.  The following:

        (true && ! false) || (false && ! true)
        echo $?

works, whereas the following:

        (! true) != (! false)
        echo $?

shows syntax error.

Is there any way to avoid redundancy in the shell script that needs this?  The
code in question is already quite complex, so adding this redundancy makes it
less readable.

> The reason it's not there is because it's not in C.

Because of performance?

-- 
Robert Millan