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Re: completion considers equals sign (=) its own word?


From: Chet Ramey
Subject: Re: completion considers equals sign (=) its own word?
Date: Thu, 17 Dec 2009 10:03:23 -0500
User-agent: Mozilla/5.0 (Macintosh; U; Intel Mac OS X 10.5; en-US; rv:1.9.1.5) Gecko/20091204 Thunderbird/3.0

On 12/15/09 6:01 AM, address@hidden wrote:
> Configuration Information [Automatically generated, do not change]:
> Machine: i486
> OS: linux-gnu
> Compiler: gcc
> Compilation CFLAGS:  -DPROGRAM='bash' -DCONF_HOSTTYPE='i486' 
> -DCONF_OSTYPE='linux-gnu' -DCONF_MACHTYPE='i486-pc-linux-gnu' 
> -DCONF_VENDOR='pc' -DLOCALEDIR='/usr/share/locale' -DPACKAGE='bash' -DSHELL 
> -DHAVE_CONFIG_H   -I.  -I../bash -I../bash/include -I../bash/lib   -g -O2 
> -Wall
> uname output: Linux swboyd-laptop 2.6.31-16-generic #53-Ubuntu SMP Tue Dec 8 
> 04:01:29 UTC 2009 i686 GNU/Linux
> Machine Type: i486-pc-linux-gnu
> 
> Bash Version: 4.0
> Patch Level: 33
> Release Status: release
> 
> Description:
>       When completing options for git I used to be able to get a list
>       of pretty formats by completing the --pretty= option. The option
>       ends in an equals sign, so the completion looks for the word
>       --pretty= in the COMP_WORDS array. It turns out that --pretty and =
>       are considered two separate words in bash4, but considered one word
>       in bash3. Is this intended?

Yes.  The programmable completion in bash-4.x uses the same set of
characters to split words as the readline word completion code.  Doing
otherwise led to too many weird inconsistencies.

If you want to remove `=' from the set of `completion word break'
characters, you can modify the COMP_WORDBREAKS variable.

Chet

-- 
``The lyf so short, the craft so long to lerne.'' - Chaucer
                 ``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, ITS, CWRU    address@hidden    http://cnswww.cns.cwru.edu/~chet/




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