Re: Ubuntu [Bug 791263] !$ works with `` but not $()

[Chet Ramey]

On 6/1/11 9:31 AM, Ralph Corderoy wrote:

> Report follows.
> 
> https://bugs.launchpad.net/ubuntu/+source/bash/+bug/791263
> 
> This is on 10.04 and also with upstream's pure bash 4.2 with no Debian
> or Ubuntu patches.
> 
>     $ echo bar >foo
>     $ >bar
>     $ ls `cat foo`
>     bar
>     $ wc !$
>     wc `cat foo`
>     0 0 0 bar
>     $ ls $(cat foo)
>     bar
>     $ wc !$
>     wc )
>     -bash: syntax error near unexpected token `)'
>     $ ls $(<foo)
>     bar
>     $ wc !$
>     wc )
>     -bash: syntax error near unexpected token `)'
>     $
> 
> I'd expect !$ to consider the last word to be $(...) just as it is happy
> with `...`.  zsh does.

Thanks for the report.  This will be fixed for the next version of bash.
In addition to $(...), process substitution and extended globbing patterns
will work as well.

Chet
-- 
``The lyf so short, the craft so long to lerne.'' - Chaucer
                 ``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, ITS, CWRU    address@hidden    http://cnswww.cns.cwru.edu/~chet/