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Calling Bash with /S
From: |
sweinberger |
Subject: |
Calling Bash with /S |
Date: |
Wed, 22 Jun 2011 09:59:45 -0700 (PDT) |
Hi All,
I am calling bash from dmake. The make file initiates the call to bash as
follows:
/bin/bash /S /c ""
The command to execute is between the double quotes. For instance
In Make File:
@ls -l ./SomeDir/*
Bash Command
/bin/bash /S /c "ls -l ./SomeDir/*"
The /S from what I see enables regular expression processing in the bash
command line, but maybe I might be wrong. In any event, the problem that I
have is the asterisk. Bash does not like it. I tried escaping it with a
backslash up to nine levels but that did not work; should only require one.
Yes, the actual command that I use is not ls. In the real example, I am
using "rm -f", but ls is a good example too and safer for experimentation.
How do I write the command line, so that it works? "ls -l ./SomeDir/\*"
does not work, nor anything else that I tried so far.
Thanks in advance,
Sarah
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- Calling Bash with /S,
sweinberger <=