Re: Inconsistent quote and escape handling in substitution part of parameter expansions.

[Chet Ramey]

On 2/28/12 1:04 PM, John Kearney wrote:

> bash treats replacement strings inconsistently in double quoted variable
> expansion.

Double-quoted pattern substitution.

> treated as literal because it is printed
> treated as quote char because otherwise it should hang waiting for '

Correct.  It acts as a quote character like unquoted ${param/pat/rep}
but does not undergo quote removal because of the double quotes.

-- 
``The lyf so short, the craft so long to lerne.'' - Chaucer
                 ``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, ITS, CWRU    chet@case.edu    http://cnswww.cns.cwru.edu/~chet/