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Re: ((i++)) no longer supported?

From: DJ Mills
Subject: Re: ((i++)) no longer supported?
Date: Thu, 3 May 2012 03:13:37 -0400

On Thu, May 3, 2012 at 2:53 AM, Pierre Gaston <address@hidden> wrote:
> On Thu, May 3, 2012 at 9:34 AM, Pan ruochen <address@hidden> wrote:
>> Hi All,
>> Suddenly I found that ((i++)) is not supported on bash.
>> Just try the following simple case:
>> $i=0; ((i++)); echo $?
>> And the result is
>> 1
>> which means an error.
>> I got the same result on GNU bash, version 4.1.2(1)-release
>> (x86_64-redhat-linux-gnu) and GNU bash, version 4.1.10(4)-release
>> (i686-pc-cygwin).
>> - BR, Ruochen
> It has always been the case, and fits the documentation since i++
> value is 0 and that is false in the arithmetic context.
> What changed is that it bash exits in this case if you use set -e.
> Some Possible workarounds:
> ((i++)) || :
> ((i+=1))
> i=$((i+1))
> and a gazillon others.

The most sane workaround would probably be to stop using set -e.

But another one, just for S&G: ((i++, 1))

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