Re: xargs combined with awk

[Steven W. Orr]

On 12/20/2012 10:43 AM, giuseppe.amatulli@gmail.com wrote:
> Hi,
> have this a for loop which is sending the "dir" variable one for each processor.
>
>
> for dir in UA_tile_tif_pop_txt UA_buf10_tile_tif_pop_txt 
> UA_buf20_tile_tif_pop_txt UA_buf30_tile_tif_pop_txt UA_buf40_tile_tif_pop_txt 
> UA_buf50_tile_tif_pop_txt ; do echo $dir ; done | xargs  -n 1 -P 6 bash -c '
> IN_UA=/weldgfs/p51/gius_urban/pop_urban/buffer_tif
> dir="$1"
>
> join -1 2  -2 1 $IN_UA/$dir/UA_block_sum_s.txt     $IN_UA/$dir/UA_popD_all.txt     
>   > $IN_UA/$dir/UA_block_sum_popD.txt
> join -1 2  -2 1 $IN_UA/$dir/UA_block_sum_popD.txt  $IN_UA/$dir/UA_hunitD_all.txt 
> > $IN_UA/$dir/UA_block_sum_popD_hunitD.txt
>
> ' _
>
> The loop works fine, no issues.
> When i'm insert an awk command in the -c ' ' _
> I get an error.
>
> e.g.
>
>
> for dir in UA_tile_tif_pop_txt UA_buf10_tile_tif_pop_txt 
> UA_buf20_tile_tif_pop_txt UA_buf30_tile_tif_pop_txt UA_buf40_tile_tif_pop_txt 
> UA_buf50_tile_tif_pop_txt ; do echo $dir ; done | xargs  -n 1 -P 6 bash -c '
> IN_UA=/weldgfs/p51/gius_urban/pop_urban/buffer_tif
> dir="$1"
>
> awk '{ print $2 }' $IN_UA/$dir/UA_block_sum_s.txt  > $IN_UA/$dir/test.txt
>
> ' _
>
>
> awk: cmd. line:1: {
> awk: cmd. line:1:  ^ unexpected newline or end of string
>
>
> I try to escape with the \ the ' and the } but no good results.
> any idea how how i can insert awk function in xargs bash -c '  '_ syntax?
>
> I would like to avoid to create an external script and called it by
> xargs bash myscript.sh

# Change this
awk '{ print $2 }' $IN_UA/$dir/UA_block_sum_s.txt  > $IN_UA/$dir/test.txt

# to this
awk \"{ print \$2 }\" $IN_UA/$dir/UA_block_sum_s.txt  > $IN_UA/$dir/test.txt

You were already in a single quoted string, so your awk code terminated it.

Steve Orr