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Re: typeset -p & manpage on it are confusing w/rt funcs

From: Linda Walsh
Subject: Re: typeset -p & manpage on it are confusing w/rt funcs
Date: Sat, 08 Jun 2013 18:44:03 -0700
User-agent: Thunderbird

Greg Wooledge wrote:
On Thu, Jun 06, 2013 at 03:48:09PM -0700, Linda Walsh wrote:
I wanted to test to see if a function was defined

imadev:~$ declare -f foo >/dev/null 2>&1 ; echo $?
imadev:~$ declare -f bar >/dev/null 2>&1 ; echo $?
    Obsolete.  See `help declare'.
But "typeset" does work in place of "declare" in the examples above.
They appear to be interchangeable, for now, in this particular case.
Yeah, I see that, I supposed I was looking for output from decl/typeset
from the -p switch showing just the funcname with any attrutes ( like export)..
just as it does for the variables... unless it is a local function and then I 
-- for the attributes.

The confusing part is having the -f and -F in the same paragraph as -p.

It looks like it is a paragraph mostly about 'p', and so you read
-p prints all names+attr Us9ing -f will restrict the display to shell functions
and -F inhibits them. --- When used with '-p'?  no -- as it ealier says 'f'
can't be used with any other args if it is used with a name.

Seems like if I type declare -p 'funcname', I get ' typeset -p include
-bash: typeset: include: not found -- I tried to use it with -f to just see
typeset -fp include
-bash: typeset: include: not found

-p can't be used with -f, but the manpage puts them in the same paragraph like
they are related switches -- where -f/-F can be used to modify the output of
-p -- which doesn't seem to be the case.

That's the confusion, really... Just some unclarity in the words, I thought.

no biggie.

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