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Re: [doc] confusion over $0 and positional parameters

From: Chet Ramey
Subject: Re: [doc] confusion over $0 and positional parameters
Date: Wed, 27 Aug 2014 08:45:48 -0400
User-agent: Mozilla/5.0 (Macintosh; Intel Mac OS X 10.9; rv:24.0) Gecko/20100101 Thunderbird/24.6.0

On 8/27/14, 8:06 AM, Stephane Chazelas wrote:
> In
>   info -f bash -n 'Invoking Bash'
> we find:
>> `-c'
>>      Read and execute commands from the first non-option ARGUMENT after
>>      processing the options, then exit.  Any remaining arguments are
>>      assigned to the positional parameters, starting with `$0'.

True, it's careless wording.  I will modify it.

The key is that the behavior makes `bash -c string command args' and
`bash command args' equivalent in how they set $0.

``The lyf so short, the craft so long to lerne.'' - Chaucer
                 ``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, ITS, CWRU    address@hidden    http://cnswww.cns.cwru.edu/~chet/

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