Re: \c-handling in $'-strings

[Chet Ramey]

On 9/2/15 5:10 PM, Helmut Karlowski wrote:

>> `\c' honor backslash escaping.  Since the character becomes \c\\, the
>> subsequent `c' and `]' are literals.
> 
> I assume this is only true for "to-be-escaped" characters, that is
> 
> $   `   "   \   <newline>
> 
> like for ".."-strings? Of course only \ is of interest here.
> 
> If that is true then the output of ksh93 for
> 
> echo $'\c\d' |od -a -> 0000000 eot  nl
> 
> is wrong? It removes the \ every time.

The proposal leaves it implementation-defined.  It specifically mentions
that you have to use \c\\ to represent <FS> to avoid ambiguity in the
backslash processing.  Bash chooses to preserve the backslash before any
unrecognized escape sequence.

-- 
``The lyf so short, the craft so long to lerne.'' - Chaucer
                 ``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, ITS, CWRU    chet@case.edu    http://cnswww.cns.cwru.edu/~chet/