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Re: declare [-+]n behavior on existing (chained) namerefs


From: Chet Ramey
Subject: Re: declare [-+]n behavior on existing (chained) namerefs
Date: Thu, 5 May 2016 14:22:15 -0400
User-agent: Mozilla/5.0 (Macintosh; Intel Mac OS X 10.10; rv:45.0) Gecko/20100101 Thunderbird/45.0

On 4/29/16 12:50 PM, Grisha Levit wrote:

> The only buggy behavior when inside of functions (ignoring scope issues)
> seems to be that `declare -n ref’ unsets the value of $ref if it previously
> pointed to a variable that is unset.
> 
> |$ f() { unset var; declare -n ref=var; declare -n ref; declare -p ref; }; f
> declare -n ref # why did the value of ref disappear? $ f() { local var;
> declare -n ref=var; declare -n ref; declare -p ref; }; f declare -n ref="var" 
> |

I fixed this as part of making other changes prompted by the discussion.


-- 
``The lyf so short, the craft so long to lerne.'' - Chaucer
                 ``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, ITS, CWRU    address@hidden    http://cnswww.cns.cwru.edu/~chet/



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