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case inside $(while true) misparsed

From: Kjetil Torgrim Homme
Subject: case inside $(while true) misparsed
Date: Wed, 01 Nov 2017 12:04:10 +0100

Configuration Information [Automatically generated, do not change]:
Machine: x86_64
OS: linux-gnu
Compiler: gcc
Compilation CFLAGS:  -DPROGRAM='bash' -DCONF_HOSTTYPE='x86_64' 
-DCONF_OSTYPE='linux-gnu' -DCONF_MACHTYPE='x86_64-unknown-linux-gnu' 
-DCONF_VENDOR='unknown' -DLOCALEDIR='/opt/bash/share/locale' -DPACKAGE='bash' 
-DSHELL -DHAVE_CONFIG_H   -I.  -I. -I./include -I./lib   -g -O2 
-Wno-parentheses -Wno-format-security
uname output: Linux scribus.ms.redpill-linpro.com 4.11.12-200.fc25.x86_64 #1 
SMP Fri Jul 21 16:41:43 UTC 2017 x86_64 x86_64 x86_64 GNU/Linux
Machine Type: x86_64-unknown-linux-gnu

Bash Version: 4.4
Patch Level: 12
Release Status: release

        I was bitten by earlier iterations of case selectors prematurely ending 
an $()
and my actual problem has been patched in the newest release (thanks!).  I came 
across a
degenerate case in my testing, though.

        foo=$(while true; do case $HOME in /*) echo abs ;; esac; done)
        bash: syntax error near unexpected token `;;'

        It works if you replace "true" with "false", or even with ":" (in which 
case it
        loops endlessly as it should)

        Use backticks, or don't write degenerate code.

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