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Re: command substitution inside parameter expansion inside "for ((;;))"


From: Chet Ramey
Subject: Re: command substitution inside parameter expansion inside "for ((;;))"
Date: Wed, 15 Nov 2017 10:28:47 -0500
User-agent: Mozilla/5.0 (Macintosh; Intel Mac OS X 10.12; rv:52.0) Gecko/20100101 Thunderbird/52.4.0

On 11/15/17 5:13 AM, Stephane Chazelas wrote:
> Hello,
> 
> $ bash -c 'for ((i = 0; $(echo 0); i++)); do echo x; done'
> 
> (OK)
> 
> $ bash -c 'for ((i = 0; ${x-`echo 0`}; i++)); do echo x; done'
> 
> (OK)
> 
> $ bash -c 'for ((i = 0; ${x-$(echo 0)}; i++)); do echo x; done'
> bash: -c: line 0: syntax error near unexpected token `newline'
> bash: -c: line 0: `for ((i = 0; ${x-$(echo 0)}; i++)); do echo x; done'
> 
> It's the same for ${x#$(echo 0)}.

This was fixed in the devel branch at the end of April, 2017.

-- 
``The lyf so short, the craft so long to lerne.'' - Chaucer
                 ``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, UTech, CWRU    address@hidden    http://cnswww.cns.cwru.edu/~chet/



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