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Re: set -u not working as expected

From: Lawrence Velázquez
Subject: Re: set -u not working as expected
Date: Sun, 2 Aug 2020 03:34:23 -0400

> On Aug 2, 2020, at 2:51 AM, Oğuz <oguzismailuysal@gmail.com> wrote:
> `u' has no members, so there's nothing to expand. If you use `${u[0]}' for
> example, you'll see an error, I think how bash and ksh behave is perfectly
> reasonable.

Agreed. Their behavior logically follows from POSIX's carveout for $@.

>> % bash -c 'set -u; typeset -i v; printf "<%s>\\n" "$v"'
>> bash: v: unbound variable
>> % ksh -c 'set -u; typeset -i v; printf "<%s>\\n" "$v"'
>> ksh: v: parameter not set
>> % zsh -c 'set -u; typeset -i v; printf "<%s>\\n" "$v"'
>> <0>
> `typeset -i v' doesn't assign `v', just gives it the integer attribute.
> Again, I can't see any problem with bash and ksh here.

Also agreed, but I was more interested in the next part...

>> % bash -c 'set -u; typeset -i v; v+=1; printf "<%s>\\n" "$v"'
>> <1>
>> % ksh -c 'set -u; typeset -i v; v+=1; printf "<%s>\\n" "$v"'
>> <1>
>> % zsh -c 'set -u; typeset -i v; v+=1; printf "<%s>\\n" "$v"'
>> <1>

...which contrasts with the behavior of let. Someone else will have
to explain this, as I don't know what to make of it.


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