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Re: local/typeset/declare -p - outputs invalid declare -- -
From: |
Alex fxmbsw7 Ratchev |
Subject: |
Re: local/typeset/declare -p - outputs invalid declare -- - |
Date: |
Mon, 31 Oct 2022 18:12:14 +0100 |
hi , sorry.. whats the purpose of local -
informational question
On Mon, Oct 31, 2022, 17:45 Emanuele Torre <torreemanuele6@gmail.com> wrote:
> Since bash 5.2, local/typeset/declare -p without argument no longer
> outputs "declare -- -" when local - is used.
>
> But local/typeset/declare -p - still outputs "declare -- -" instead of
> "local -".
>
> bash-5.1$ a () { local -; local -p; declare -p -; typeset -p -;
> local -p - ;}
> bash-5.1$ a
> declare -- -
> declare -- -
> declare -- -
> declare -- -
>
> bash-5.2$ a () { local -; local -p; declare -p -; typeset -p -;
> local -p - ;}
> bash-5.2$ a
> local -
> declare -- -
> declare -- -
> declare -- -
>
>