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From: | Chet Ramey |
Subject: | Re: local/typeset/declare -p - outputs invalid declare -- - |
Date: | Wed, 16 Nov 2022 14:05:56 -0500 |
User-agent: | Mozilla/5.0 (Macintosh; Intel Mac OS X 10.15; rv:102.0) Gecko/20100101 Thunderbird/102.4.2 |
On 11/16/22 12:12 PM, Emanuele Torre wrote:
The 31f4d468b60eb27d768ef56d0a8b4982346465d9 commit on the devel branch, addressed this issue, but only partially: bash-5.1$ ./bash --version |& head -n 1 GNU bash, version 5.2.9(6)-maint (x86_64-pc-linux-gnu) bash-5.1$ ./bash -c 'a () { local -; local -p; declare -p -; typeset -p -; local -p - ;}; a' local - declare -- - declare -- - local - `local -p -' no longer prints "declare -- -", but `declare -p -', and `typeset -p -' still do.
It doesn't matter. `local -' is the only way to save and restore the options; `declare -p -' and `typeset -p -' should have no special meaning.
-- ``The lyf so short, the craft so long to lerne.'' - Chaucer ``Ars longa, vita brevis'' - Hippocrates Chet Ramey, UTech, CWRU chet@case.edu http://tiswww.cwru.edu/~chet/
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