[bug #13041] -i and - shouldn't be exclusive

[anonymous]

URL:
  <http://savannah.gnu.org/bugs/?func=detailitem&item_id=13041>

                 Summary: -i and - shouldn't be exclusive
                 Project: findutils
            Submitted by: None
            Submitted on: Mon 05/09/2005 at 23:59
                Category: xargs
                Severity: 3 - Normal
              Item Group: Wrong result
                  Status: None
                 Privacy: Public
             Assigned to: None
         Originator Name: Alejandro Forero Cuervo
        Originator Email: address@hidden
             Open/Closed: Open
                 Release: 4.1.20
           Fixed Release: None

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Details:

I can't xargs to work as I would expect it when I give it both the ‘-i’ and
‘-l’ args.  Using ‘-i’ specifies ‘-l1’ (as the documentation indicates) and
using ‘-l’ seems to disable the functionality provided by ‘-i’.

This can be evidenced by using the following program:

main ( int argc, char **argv ) { int i; for (i = 0; i < argc; i ++) {
printf("Arg %d: [%s]\n", i, argv[i]); } }

When I build it and run it from xargs, I get the following:

> echo -e 'a\nb\nc' | xargs -l10 -i ./test {}
Arg 0: [./test]
Arg 1: [a]
Arg 0: [./test]
Arg 1: [b]
Arg 0: [./test]
Arg 1: [c]
> echo -e 'a\nb\nc' | xargs -i -l10 ./test {}
Arg 0: [./test]
Arg 1: [{}]
Arg 2: [a]
Arg 3: [b]
Arg 4: [c]
> 

I was expecting to be able to combine ‘-i’ and ‘-l’ to get:

Arg 0: [./test]
Arg 1: [a]
Arg 2: [b]
Arg 3: [c]

I don't see anything in the semantics of ‘-i’ and ‘-l’ that makes them
exclude each other.  Of course, in ‘-i’, the replace string (‘{}’) would get
replaced with as many tokens from the input as permitted.



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CC Address                          | Comment
------------------------------------+-----------------------------
bachue --AT-- bachue --DOT-- com    | Originator Email




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