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Re: [bug-gawk] How to take some variables from bash to awk?
From: |
Davide Brini |
Subject: |
Re: [bug-gawk] How to take some variables from bash to awk? |
Date: |
Fri, 16 Nov 2012 16:30:37 +0100 |
On Fri, 16 Nov 2012 09:00:35 -0600, Peng Yu <address@hidden> wrote:
> Hi,
>
> I want pass variables in bash to be used in awk in the following
> example. But it gives me some error that I have on idea how to fix.
> Does anybody know what is wrong? Thanks!
>
> ~/linux/test/awk/lang/pipe/|$ cat ./main_bash_var.sh
> #!/usr/bin/env bash
>
> awk -v cmd="sort -k 1,1n" 'BEGIN{print cmd}{print $0 | cmd }' <<EOF
> 3 4
> 1 2
> EOF
>
>
> options=(-k 1,1n)
> echo address@hidden
> awk -v cmd="sort address@hidden" 'BEGIN{print cmd}{print $0 | cmd }' <<EOF
> 3 4
> 1 2
> EOF
>
> ~/linux/test/awk/lang/pipe/|$ ./main_bash_var.sh
> sort -k 1,1n
> 1 2
> 3 4
> -k 1,1n
> awk: fatal: cannot open file `BEGIN{print cmd}{print $0 | cmd }' for
> reading (No such file or directory)
Awk is seeing:
awk -v cmd='sort -k' '1,1n' 'BEGIN{print cmd}{print $0 |cmd }'
--
D.