
From:  Manuel Collado 
Subject:  Re: [buggawk] GAWK 4.1: Division with Arbitrary Precision Integers 
Date:  Wed, 07 Aug 2013 10:35:55 +0200 
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El 06/08/2013 22:07, Katherine Wasserman escribiÃ³:
Hi AndyPerhaps something like div(numerator, denominator, result) where the result will be an array with a "quot" element and a "rem" element. I don't think it's possible to have a function that returns an array, but I'm not certain...Maybe div() could just return the quotient and an optional third argument could return the remainder. This would save the extra steps needed to pull apart an array and most often throw out the remainder portion.
Yes. This seems the simplest approach.
Also the '%' operator seems to work ok with bignums so there already is a useable remainder function. Thanks, Katie At 02:08 PM 8/6/2013, Andrew J. Schorr wrote:Hi, On Tue, Aug 06, 2013 at 01:01:40AM 0400, Katherine Wasserman wrote:There is currently no way to preform division of arbitrary precision integers in gawk, the system will always convert numbers to floating point when using the '/' operator. Per Aharon , there appear to be at least two ways around this: 1) change the semantics of the '/' operator.I don't think we could change the behavior of the '/' operator unless we introduced a new option to select this behavior. That doesn't sound workable to me...2) introduce a new function for integer division. I think that the later is both cleaner and useful as a function even without the MPFR/MP extensions loaded.I think this is the right solution. There is a "div" function in ISO C that does what we want: http://pubs.opengroup.org/onlinepubs/9699919799/functions/div.html
BTW, the Pascal language (and some derivatives) has always had two division operators for integers:
integer / integer > float integer div integer > integer So "div" seems a common name for the integer division operator/function.
Perhaps something like div(numerator, denominator, result) where the result will be an array with a "quot" element and a "rem" element. I don't think it's possible to have a function that returns an array, but I'm not certain... Regards, Andy
Regards,  Manuel Collado  http://lml.ls.fi.upm.es/~mcollado
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