Re: [bug-gawk] How to unescape a string?

[david kerns]

here's sed:
$ echo "a\\\\b\\\"" ; echo "a\\\\b\\\"" | sed -e 's/\\\(.\)/\1/g'
a\\b\"
a\b"

...trying to use sed from awk ... I'm still missing something

$ awk 'BEGIN{a="a\\\\b\\\"";q=sprintf("%c",39);print a;c="sed -e
"q"s/\\\\\\(.\\)/\\1/g"q;print c;print a |& c;c |& getline b;close(c);print
b}'
a\\b\"
sed -e 's/\\\(.\)/\1/g'
(hangs)


On Tue, Oct 23, 2018 at 4:36 PM david kerns <address@hidden> wrote:

>
> I was hoping this would, but it doesn't .. perhaps it will spur someone
> else :/
>
> awk 'BEGIN { a ="a\\\\b\\\""; print a; gensub(/\\(.)/, "\1", "g", a);
> print a }'
> a\\b\"
> a\\b\"
>
>
> On Tue, Oct 23, 2018 at 2:35 PM Peng Yu <address@hidden> wrote:
>
>> Hi,
>>
>> I have a string in which the double quote character is escaped as \"
>> (baskslash character and double quote character) and the backslash
>> character is escaped as \\ (double backslash). Does anybody know a
>> simple way to unescape such a string in awk? (The following is a
>> simple example of the input and the output.) Thanks.
>>
>> a\\b\" -> a\b"
>>
>> --
>> Regards,
>> Peng
>>
>>