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shiftf is not parallel
From: |
Kalle Olavi Niemitalo |
Subject: |
shiftf is not parallel |
Date: |
14 Apr 2001 21:01:27 +0300 |
In GNU Emacs 20.6.4 (i386-debian-linux-gnu, X toolkit)
of Thu Jun 1 2000 on PC486
configured using `configure i386-debian-linux-gnu --prefix=/usr
--sharedstatedir=/var/lib --libexecdir=/usr/lib --localstatedir=/var/lib
--infodir=/usr/share/info --with-pop=yes --with-x=yes --with-x-toolkit=yes'
According to Info: (cl)Modify Macros, "(shiftf A B C D) is
equivalent to (prog1 A (psetf A B B C C D)) except that the
subforms of A, B, and C are actually evaluated only once each and
in the apparent order." This implies that D is evaluated using
the original values of A, B and C. However:
(let ((a 1) (b 2))
(shiftf a b (cons a b))
b)
=> (2 . 2)
(let ((a 1) (b 2))
(prog1 a
(psetf a b
b (cons a b)))
b)
=> (1 . 2)
I believe both expressions should return the same thing.
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