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bug#41347: 28.0.50; calculator.el: Cannot input negative exponents
From: |
Chris Zheng |
Subject: |
bug#41347: 28.0.50; calculator.el: Cannot input negative exponents |
Date: |
Sun, 17 May 2020 13:53:12 +0800 |
Hello,
With current master, starting Emacs with `-Q`:
1. M-x calculator
2. Input 1e-3 RET
You will get 1 instead of 0.001. I believe this happens since Emacs 26.1. The
root cause is the `calculator-string-to-number` function in lisp/calculator.el.
Now the function gives
(calculator-string-to-number "1e-3") => 1.0
(calculator-string-to-number "1e3") => 1000.0
(calculator-string-to-number "1e") => 1.0
The funcional code is
(replace-regexp-in-string
"[eE][+-]?\\([^0-9].*\\)?$" "e0\\1" str)
It changes `1e-3` to `1e0-3` that is recognized as 1. I have a possible fix attached below. Please see if it is correct.
Thank you,
Chris Zheng
From 7693d7072e4787c4b0663f490be5d83c1d9a6ee3 Mon Sep 17 00:00:00 2001
From: Chris Zheng <chriszheng99@gmail.com>
Date: Sun, 17 May 2020 13:43:35 +0800
Subject: [PATCH 1/1] Fix calculator exponent input
* lisp/calculator.el (calculator-string-to-number): Change the regexp
to correctly deal with negative exponents.
---
lisp/calculator.el | 2 +-
1 file changed, 1 insertion(+), 1 deletion(-)
diff --git a/lisp/calculator.el b/lisp/calculator.el
index 7e0b2fcc6a..fa3eb19099 100644
--- a/lisp/calculator.el
+++ b/lisp/calculator.el
@@ -863,7 +863,7 @@ calculator-string-to-number
(let* ((str (replace-regexp-in-string
"\\.\\([^0-9].*\\)?$" ".0\\1" str))
(str (replace-regexp-in-string
- "[eE][+-]?\\([^0-9].*\\)?$" "e0\\1" str)))
+ "[eE]\\([+-]?\\)?$" "e\\10" str)))
(float (string-to-number str)))))
(defun calculator-push-curnum ()
--
2.16.1.windows.1
- bug#41347: 28.0.50; calculator.el: Cannot input negative exponents,
Chris Zheng <=