[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]
bug#61281: “`(a \, b)” equals to “`(a . , b)”
From: |
Michael Heerdegen |
Subject: |
bug#61281: “`(a \, b)” equals to “`(a . , b)” |
Date: |
Wed, 08 Feb 2023 00:36:37 +0100 |
User-agent: |
Gnus/5.13 (Gnus v5.13) |
Drew Adams <drew.adams@oracle.com> writes:
> > It is obvious that the Lisp implementation of
> > the "`" macro receives symbolic expressions.
>
> This is about the Lisp reader. When you write
> ",X" in that explanatory comment it's ambiguous
> whether "X" is an arbitrary sequence of chars
> or some Lisp sexp (read separately after reading
> the ","). ",abcd" is handled differently than
> ", abcd", as we've gone over several times now.
So you want to add to the text that X is an expression? Or anything
else? We surely don't want to explain the complete parsing process
there. What do you suggest to write in that comment?
Michael.
- bug#61281: “`(a \, b)” equals to “`(a . , b)”, (continued)
- bug#61281: “`(a \, b)” equals to “`(a . , b)”, Drew Adams, 2023/02/05
- bug#61281: “`(a \, b)” equals to “`(a . , b)”, Michael Heerdegen, 2023/02/05
- bug#61281: “`(a \, b)” equals to “`(a . , b)”, Drew Adams, 2023/02/05
bug#61281: “`(a \, b)” equals to “`(a . , b)”, Michael Heerdegen, 2023/02/05
- bug#61281: “`(a \, b)” equals to “`(a . , b)”, Drew Adams, 2023/02/06
- bug#61281: “`(a \, b)” equals to “`(a . , b)”, Drew Adams, 2023/02/06
- bug#61281: “`(a \, b)” equals to “`(a . , b)”, Michael Heerdegen, 2023/02/06
- bug#61281: “`(a \, b)” equals to “`(a . , b)”, Drew Adams, 2023/02/06
- bug#61281: “`(a \, b)” equals to “`(a . , b)”, Michael Heerdegen, 2023/02/06
- bug#61281: “`(a \, b)” equals to “`(a . , b)”, Drew Adams, 2023/02/07
- bug#61281: “`(a \, b)” equals to “`(a . , b)”,
Michael Heerdegen <=
- bug#61281: “`(a \, b)” equals to “`(a . , b)”, Drew Adams, 2023/02/07
- bug#61281: “`(a \, b)” equals to “`(a . , b)”, Michael Heerdegen, 2023/02/08
- bug#61281: “`(a \, b)” equals to “`(a . , b)”, Drew Adams, 2023/02/08