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Re: "seq .1 .1" would mistakenly generate no output on FreeBSD 6.1
From: |
Jim Meyering |
Subject: |
Re: "seq .1 .1" would mistakenly generate no output on FreeBSD 6.1 |
Date: |
Wed, 21 Nov 2007 13:40:18 +0100 |
Bruno Haible <address@hidden> wrote:
> Jim Meyering wrote:
>> 0.1L == (long double) 0.1
>> evaluates to true.
>
> OK, so let's try a runtime test instead of a compile-time test.
>
> What does this program give?
>
> #include <stdio.h>
> #include <stdlib.h>
> long double a = 4.0L;
> long double b = 5.0L;
> int main()
> {
> long double x = a / b;
> long double y = strtold ("0.8", NULL);
> printf ("%d\n", x == y);
> printf ("x = %04X%04X%04X\n", ((unsigned int *) &x)[2],
> ((unsigned int *) &x)[1], ((unsigned int *) &x)[0]);
> printf ("y = %04X%04X%04X\n", ((unsigned int *) &y)[2],
> ((unsigned int *) &y)[1], ((unsigned int *) &y)[0]);
> return 0;
> }
Yep. That ought to do it:
freebsd6$ ./a.out
0
x = BFBF3FFECCCCCCCCCCCCD000
y = BFBF3FFECCCCCCCCCCCCCCCD
- Re: "seq .1 .1" would mistakenly generate no output on FreeBSD 6.1, Jim Meyering, 2007/11/20
- Re: "seq .1 .1" would mistakenly generate no output on FreeBSD 6.1, Paul Eggert, 2007/11/20
- Re: "seq .1 .1" would mistakenly generate no output on FreeBSD 6.1, Bruno Haible, 2007/11/20
- Message not available
- Re: "seq .1 .1" would mistakenly generate no output on FreeBSD 6.1, Bruno Haible, 2007/11/20
- Re: "seq .1 .1" would mistakenly generate no output on FreeBSD 6.1, Paul Eggert, 2007/11/20
- Re: "seq .1 .1" would mistakenly generate no output on FreeBSD 6.1, Bruno Haible, 2007/11/20
- Re: "seq .1 .1" would mistakenly generate no output on FreeBSD 6.1, Jim Meyering, 2007/11/21
- Re: "seq .1 .1" would mistakenly generate no output on FreeBSD 6.1, Bruno Haible, 2007/11/21
- Re: "seq .1 .1" would mistakenly generate no output on FreeBSD 6.1,
Jim Meyering <=
- Re: "seq .1 .1" would mistakenly generate no output on FreeBSD 6.1, Paul Eggert, 2007/11/21
- Re: "seq .1 .1" would mistakenly generate no output on FreeBSD 6.1, Paul Eggert, 2007/11/21