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Re: -frepo does not create repository
From: |
Ronald Fischer |
Subject: |
Re: -frepo does not create repository |
Date: |
3 May 2002 01:27:50 -0700 |
address@hidden (Eray Ozkural) wrote in message news:<address@hidden>...
> On Thursday 02 May 2002 11:32, Ronald Fischer wrote:
> > template<typename T> extern void f(T);
>
> Is extern required there?
No, but it should not do any harm either. If I leave it out, the
function would have by default extern linkage. I have the habit
of writing the "extern" specifier in front
of declarations of functions with extern linkage.
Ronald
- -frepo does not create repository, Ronald Fischer, 2002/05/02
- Re: -frepo does not create repository, Eray Ozkural, 2002/05/02
- Re: -frepo does not create repository,
Ronald Fischer <=
- Re: -frepo does not create repository, Eray Ozkural, 2002/05/05
- Re: -frepo does not create repository, Ronald Fischer, 2002/05/06
- Re: -frepo does not create repository, Eray Ozkural, 2002/05/06
- Re: -frepo does not create repository, Ronald Fischer, 2002/05/07
- Re: -frepo does not create repository, Eray Ozkural, 2002/05/07
- Re: -frepo does not create repository, André Pönitz, 2002/05/07
- Re: -frepo does not create repository, Eray Ozkural, 2002/05/08
- Re: -frepo does not create repository, André Pönitz, 2002/05/13
- Re: -frepo does not create repository, Eray Ozkural, 2002/05/13