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Re: XMLFS for GSoC

From: olafBuddenhagen
Subject: Re: XMLFS for GSoC
Date: Thu, 7 Apr 2011 23:35:37 +0200
User-agent: Mutt/1.5.20 (2009-06-14)


On Thu, Apr 07, 2011 at 09:09:35PM +0100, Michael Walker wrote:

> > I don't think the XSLT translator should present a directory tree as
> > output. Nothing in XSLT requires the output to be XML.
> Aha, I had a feeling I was misunderstanding something somewhere. In
> that case, xslt would be even simpler - the code would be pretty much
> the same as unxmlfs (turn an xmlfs directory tree into an internal DOM
> representation and present it as output via trivfs), but just with a
> transformation performed.

> In fact, if that's the case maybe even just a "--xslt=FILE" option to
> unxmlfs would do the trick.

I briefly considered this, but I think we should rather go for the
opposite: let the XSLT translator take files as input. If directory
input is desired, it can always be set on top of unxml.

(BTW, the naming is rather confusing -- unxml actually turns the
underlying structure *into* XML... Maybe we should use more explicit
names instead: something like xml2dir and dir2xml perhaps.)

> However, XSLT is commonly used to turn one XML document into another,
> so perhaps there should be an option to try and present it as a
> directory tree,

Again, it seems saner to put another xmlfs on top if this is required.


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