[bug #34608] comparison of unsigned expression < 0 is always false

[Paul D. Smith]

Update of bug #34608 (project make):

                  Status:                    None => Not A Bug              
             Open/Closed:                    Open => Closed                 

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Follow-up Comment #1:

It turns out that this warning is actually intentional.  If you follow this
through you'll see it ends up in an invocation of this macro:

/* Nonzero if the integer type T is signed.  */
#define INTEGER_TYPE_SIGNED(t) ((t) -1 < 0)

The idea is to determine whether a type is signed or not, and to do this we
cast a negative number to the type and see if it's still negative (less than
0).  If it is then the type is signed; if not, not.

For systems where the type we pass in is actually unsigned (in this case
uintmax_t) you'll get this warning.  However the behavior of the program is
exactly what we expect and want.

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