[bug #45252] $(MAKE) not recognized in output of $(call)

[anonymous]

URL:
  <http://savannah.gnu.org/bugs/?45252>

                 Summary: $(MAKE) not recognized in output of $(call)
                 Project: make
            Submitted by: None
            Submitted on: Wed 03 Jun 2015 06:36:58 PM UTC
                Severity: 3 - Normal
              Item Group: Bug
                  Status: None
                 Privacy: Public
             Assigned to: None
             Open/Closed: Open
         Discussion Lock: Any
       Component Version: SCM
        Operating System: Any
           Fixed Release: None
           Triage Status: None

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Details:

A sub-make invoked by `$(call foo)` is not recognized as a sub-make, so a `+'
must be added to the command returned by foo for `make -jN` to work. Example
follows.


define foo
        $(MAKE) bar
endef

default:
        $(call foo)

bar:






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