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[bug #65685] Submake starts its own jobserver when its recipe contains $
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From: |
Dmitry Goncharov |
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Subject: |
[bug #65685] Submake starts its own jobserver when its recipe contains $(MAKE) $(MFLAGS) |
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Date: |
Mon, 6 May 2024 21:37:56 -0400 (EDT) |
Follow-up Comment #3, bug #65685 (group make):
> The way I remember it is that if we see a valid jobserver-auth argument, we
ignore the value of -j.
My understanding was that we ignore -j that comes from MAKEFLAGS, we still
honor -j specified on the command line.
> I wonder if we should simply keep the same behavior for both; if we see a
jobserver-auth on the command line we also ignore -j.
My concern is that ignoring -j specified on the command line would cause the
submake in the following example run within the parent jobserver.
all:; $(MAKE) $(MFLAGS) -j3
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