I meant: i was just simulating a simple communication system using GnuRadio, and i just have the transmitted bits connected with a noise source (gr.noise_source_c(gr.GR_GAUSSIAN, noise_voltage)). Now the only thing left is the bit energy. :) Thank you!!!
----- Original Message ----
From: George Nychis <address@hidden>
To: Bill Stevenson <address@hidden>
Cc: address@hidden
Sent: Sunday, April 13, 2008 11:50:41 PM
Subject: Re: [Discuss-gnuradio] two questions about the general communication system
So... if the noise channel is on your laptop, you must have generated
this channel? Is it a simulated channel? Are you specifying the noise
power?
You're not giving us much information.
- George
Bill Stevenson wrote:
> Thank you! What i am trying to do is very simple: I don't use USRP, i
> just used a vector as a bit source and have it modulated and transmitted
> through a noise channel (on my laptop ^.^ ). Now i can set the value of
> noise's amplitude, but there seems to be no way to determine the bit
> energy! How to get it? Thank you!!!
>
> Bill
>
> ----- Original Message ----
> From: Daniel Halperin <
address@hidden>
> To: Brian Padalino <
address@hidden>
> Cc: Bill Stevenson <
address@hidden>;
address@hidden> Sent: Sunday, April 13, 2008 8:18:14 PM
> Subject: Re: [Discuss-gnuradio] two questions about the general
> communication system
>
> -----BEGIN PGP SIGNED MESSAGE-----
> Hash: SHA1
>
> On Apr 13, 2008, at 1:28 PM, Brian Padalino wrote:
> > On Sun, Apr 13, 2008 at 2:38 PM, Bill Stevenson
> > <
address@hidden <mailto:
address@hidden>>
wrote:
> >>
> >> Thank you George!
> >>
> >> I am just wondering when we calculate BER, how can we determine the
> >> value of
> >> bit energy? Thank u!
> >
>
> If you look through the relevant emails on the list, it seems no one
> really understands the translation between the short values from the
> USRP and absolute energy --- ADC and processing behavior complicate
> the issue. However, it is much easier to estimate the ratio of Signal
> to Noise --- this is a relative quantity. Just figure out receiver
> power in the absence of a signal and in the presence of one...
>
> - -Dan
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